JZ12 数值的整数次方

https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00

public class Solution {
    public double Power(double base, int exponent) {
        if (base == 0) return base;
        
        if (exponent < 0) {
            base = 1 / base;
            exponent = -exponent;
        }
        
        double result = 1.0;
        for(int i = 0; i < exponent; i++) 
            result *= base;
        return result;
  }
}